document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=924002>Question 924002</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 25. The sum of the tens and hundreds digits of a three-digit number is 12. The units digit is 0. If the tens and hundreds digits were interchanged, the number would be increased by 540. Find the original number.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #560531 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=560531\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 100x+10y+0 be the number<BR>\n" );
document.write( "We are told that:<BR>\n" );
document.write( "x+y=12---eq1<BR>\n" );
document.write( "We are also told that:<BR>\n" );
document.write( "100y+10x+0=100x+10y+0+540<BR>\n" );
document.write( "90x-90y=-540<BR>\n" );
document.write( "x-y=-6---------eq2\r<BR>\n" );
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document.write( "add eq1 and eq2<BR>\n" );
document.write( "2x=6<BR>\n" );
document.write( "x=3------ the 100s digit<BR>\n" );
document.write( "substitute x=3 in eq2:<BR>\n" );
document.write( "3-y=-6<BR>\n" );
document.write( "y=9 -----the 10s digit<BR>\n" );
document.write( "Sooo the original number is 390\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "3+9=12<BR>\n" );
document.write( "12=12<BR>\n" );
document.write( "930=390+540<BR>\n" );
document.write( "930=930\r<BR>\n" );
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document.write( "Hope this helps----ptaylor<BR>\n" );
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