document.write( "Question 77895: how can i simplify by combining like terms?\r
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Algebra.Com's Answer #56053 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
\"%2863%5E%28-2%29%29%2A%2828%5E5%29%2A7\"
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\n" ); document.write( "The negative exponent can be changed to a positive exponent if the 63 is moved to a denominator.
\n" ); document.write( "This would make the problem:
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\n" ); document.write( "\"%281%2F63%5E2%29%2A%2828%5E5%29%2A7\"
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\n" ); document.write( "Now factor the 63 into \"%289%2A7%29\" and the 28 into \"4%2A7\". Substitute these into the
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\n" ); document.write( "\"%281%2F%289%2A7%29%5E2%29%2A%28%284%2A7%29%5E5%29%2A7\"
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\n" ); document.write( "by the power rule of exponents, the terms inside the parentheses each get raised to the
\n" ); document.write( "power associated with the brackets. This converts the problem to:
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\n" ); document.write( "\"1%2F%289%5E2%2A7%5E2%29%2A%284%5E5%29%2A%287%5E5%29%2A7\"
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\n" ); document.write( "in the numerator multiply the terms containing 7 by adding exponents (remember that 7
\n" ); document.write( "is the same as \"%287%5E1%29\") to get:
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\n" ); document.write( "\"1%2F%289%5E2%2A7%5E2%29%2A+%284%5E5%29%2A%287%5E6%29\"
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\n" ); document.write( "divide the \"7%5E2\" in the denominator into the \"7%5E6\" in the numerator by subtracting
\n" ); document.write( "the exponents to get \"7%5E%286-2%29+=+7%5E4\". This reduces the problem to:
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\n" ); document.write( "\"1%2F%289%5E2%29%2A+%284%5E5%29%2A%287%5E4%29+=+%28%284%5E5%29%2A%287%5E4%29%29%2F9%5E2\"
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\n" ); document.write( "there are no more factors in the numerator that are common with factors in the denominator.
\n" ); document.write( "You could, if you wish, factor the 4 of the first term into the numerator into 2*2 and
\n" ); document.write( "the 9 in the denominator into 3*3 to get:
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\n" ); document.write( "\"%28%28%282%2A2%29%5E5%29%2A7%5E4%29%2F%283%2A3%29%5E2\" which would expand to:
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\n" ); document.write( "\"%28%282%5E5%29%2A%282%5E5%29%2A7%5E4%29%2F%283%5E2%2A3%5E2%29+\"
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\n" ); document.write( "but that doesn't accomplish much. Or you could multiply everything out to get:
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\n" ); document.write( "\"2458624%2F81\"
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\n" ); document.write( "Hope this helps you to see how to work this problem.
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