document.write( "Question 923981: 1/A batch contains 10 transistors of which three are defective. If three are chosen, in how many ways can one get two defective?\r
\n" ); document.write( "\n" ); document.write( "2/ Three marbles are chosen from an urn that contains 5 reds, 4 white, and 3 blue marbles. how many samples if we choose all three of the same color?\r
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Algebra.Com's Answer #560520 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first one to get you started.\r
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\n" ); document.write( "\n" ); document.write( "10 transistors
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\n" ); document.write( "\n" ); document.write( "Number of ways to get exactly 2 defective\r
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\n" ); document.write( "\n" ); document.write( "(3 C 2)*(7 C 1) = (3)*(7) = 21\r
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\n" ); document.write( "\n" ); document.write( "There are 21 ways to pick exactly 2 defective transistors (out of 3 selected transistors).\r
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\n" ); document.write( "\n" ); document.write( "Side note: I'm using the combination formula . Many calculators such as the TI84 have this formula built in (let me know if you need steps on how to use it).\r
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\n" ); document.write( "\n" ); document.write( "Another side note: 3 C 2 represents picking exactly 2 bad transistors out of 3. 7 C 1 represents picking exactly 1 good transistor out of 7.
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