document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=923548>Question 923548</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello.A problem for which solution is required<BR>\n" );
document.write( "a)Find the curved surface area of a closed cylinder petrol storage tank that is 4.2m in diameter and 4.5m in height.<BR>\n" );
document.write( "b)How much steel was used if 1/12 (one twelfth) of the steel was wasted in making the tank.<BR>\n" );
document.write( "Thanks and regards.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #560495 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=560495\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a)Find the curved surface area of a closed cylinder petrol storage tank that is 4.2m in diameter and 4.5m in height.<BR>\n" );
document.write( "The curved surface area is the circumference of the tank times the height<BR>\n" );
document.write( "A =<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A4.2+%2A+4.5 ALIGN=MIDDLE  ALT=\"pi%2A4.2+%2A+4.5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "A = 59.376 sq/m<BR>\n" );
document.write( ":<BR>\n" );
document.write( "b)How much steel was used if 1/12 (one twelfth) of the steel was wasted in making the tank.<BR>\n" );
document.write( "The amt of steel to make the tank is the curved surface area plus the bottom and top.<BR>\n" );
document.write( "A = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%28pi%2A4.2%5E2%29 ALIGN=MIDDLE  ALT=\"2%28pi%2A4.2%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > + 59.376<BR>\n" );
document.write( "A = 170.2 sq/m of steel in the tank<BR>\n" );
document.write( ":<BR>\n" );
document.write( "1/12 or .08333 was wasted, therefore 11/12 or .9166 of the total steel = 170.2<BR>\n" );
document.write( ".91666t = 170.2<BR>\n" );
document.write( "t = 170.2/.916666<BR>\n" );
document.write( "t = 185.7 sq/m of steel used to make the tank </SPAN>\n" );
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