document.write( "Question 923954: Use algebraic procedures to find the exact solution(s) of the equation.
\n" ); document.write( "log(6x-21)=2+log(x-9)
\n" ); document.write( "I am taking an online class so I have to learn this stuff by myself pretty much. I have looked everywhere for how to do this problem and I can't find anything. I would really appreciate a step-by-step answer.Thank you!
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Algebra.Com's Answer #560486 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"log%28%286x-21%29%29=2%2Blog%28%28x-9%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%286x-21%29%29-log%28%28x-9%29%29=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%28%286x-21%29%2F%28x-9%29%29%29=2\" Use log rule #2 from this page\r
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\n" ); document.write( "\n" ); document.write( "\"%286x-21%29%2F%28x-9%29=10%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"%286x-21%29%2F%28x-9%29=100\" Convert to exponential form (logs without stated bases are by default in base 10)\r
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\n" ); document.write( "\n" ); document.write( "\"6x-21=100%28x-9%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"6x-21=100x-900\"\r
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\n" ); document.write( "\n" ); document.write( "\"6x-21%2B900=100x\"\r
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\n" ); document.write( "\n" ); document.write( "\"-21%2B900=100x-6x\"\r
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\n" ); document.write( "\n" ); document.write( "\"879=94x\"\r
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\n" ); document.write( "\n" ); document.write( "\"94x=879\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=879%2F94\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "The exact answer is \"x=879%2F94\"\r
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\n" ); document.write( "\n" ); document.write( "Let me know if that helps or not. Thanks.\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, feel free to email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "My Website: http://www.freewebs.com/jimthompson5910/home.html\r
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