document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=923670>Question 923670</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has three different acid solutions. The first acid solution contains 20% acid, the second contains 30% and the third contains 70%. He wants to use all three solutions to obtain a mixture of 144 liters containing 40% acid, using 3 times as much of the 70% solution as the 30% solution. How many liters of each solution should be used?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #560473 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=560473\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist has three different acid solutions. <BR>\n" );
document.write( "The first acid solution contains 20% acid, the second contains 30% and the third contains 70%.<BR>\n" );
document.write( " He wants to use all three solutions to obtain a mixture of 144 liters containing 40% acid, using 3 times as much of the 70% solution as the 30% solution.<BR>\n" );
document.write( " How many liters of each solution should be used?<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Let a = amt of 20% solution<BR>\n" );
document.write( "Let b = amt of 30% solution<BR>\n" );
document.write( "then \"using 3 times as much of the 70% solution as the 30%.\"; therefore:<BR>\n" );
document.write( "3b = amt of 70% solution<BR>\n" );
document.write( ":<BR>\n" );
document.write( "A typical mixture equation, using the decimal equiv of %<BR>\n" );
document.write( ".2a + .3b + .7(3b) = .4(144)<BR>\n" );
document.write( ".2a + .3b + 2.1b = 57.6<BR>\n" );
document.write( ".2a + 2.4b = 57.6<BR>\n" );
document.write( "We know that a = (144-4b); replace a<BR>\n" );
document.write( ".2(144-4b) + 2.4b = 57.6<BR>\n" );
document.write( "28.8 - .8b + 2.4b = 57.6<BR>\n" );
document.write( "1.6b = 57.6 - 28.8<BR>\n" );
document.write( "1.6b = 28.8<BR>\n" );
document.write( "b = 28.8/1.6<BR>\n" );
document.write( "b = 18 liters of of the 30% solution<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3(18) = 54 liters of the 70% solution<BR>\n" );
document.write( "a = 144 - 4(18)<BR>\n" );
document.write( "a = 72 liters of the 20% solution<BR>\n" );
document.write( ";<BR>\n" );
document.write( ":<BR>\n" );
document.write( "See if this checks out<BR>\n" );
document.write( ".2(72) + .3(18) + .7(54) = .4(144)<BR>\n" );
document.write( "14.4 + 5.4 + 37.8 = 57.6 </SPAN>\n" );
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