document.write( "Question 78146: Hi,\r
\n" ); document.write( "\n" ); document.write( "Here is the problem I am having troubles with. Any help would be greatly appreciated
\n" ); document.write( "Find the equation, in standard form, with all integer coefficients, of the line perpendicular to x + 2y = 8 and passing through (1, -6).
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Algebra.Com's Answer #56047 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
x+2y=8
\n" ); document.write( "2y=-x+8
\n" ); document.write( "y=-x/2+8/2
\n" ); document.write( "y=-x/2+4 THUS THIS LINE HAS A SLOPE OF(m)=(-1/2)
\n" ); document.write( "THUS A PERPENDICULAR LINE HAS A SLOPE OF +2.
\n" ); document.write( "NOW REPLACE THE X & Y TERMS WITH 1 & -6 & SOLVE FOR THE Y INTERCEPT(b)
\n" ); document.write( "Y=mX+b
\n" ); document.write( "-6=2*1+b
\n" ); document.write( "-6=2+b
\n" ); document.write( "b=-6-2
\n" ); document.write( "b=-8 THE Y INTERCEPT. THUS THE EQUATION IS:
\n" ); document.write( "Y=2X-8
\n" ); document.write( "the red line is the original line & the green line is the perpendicular line.
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+y+=+-x%2F2+%2B4%2C+y+=+2x+-8%29+\" (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions y = -x/2 +4 and y = 2x -8).
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