document.write( "Question 923890: A rectangle is 3 times as long as it is wide. If the length is increased by 6 and the width by 8, the area is increased by 108. Find the perimeter of the original rectangle. Thanks for your help. \n" ); document.write( "

Algebra.Com's Answer #560450 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "     .
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document.write( "A = Lw
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document.write( ".....Original width =  w and L = 3w
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document.write( "(3w+6)(w+8) - (3w)w= 108
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document.write( "3w^2 + 30w + 48 - 3w^2 = 108
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document.write( "30w = 60
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document.write( "w = 2   and L = 6 
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document.write( "......
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document.write( "P = 2L + 2w
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document.write( "P(original) = 2*2 + 2*6 = 16units \n" );
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