document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=923875>Question 923875</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The random variable x has a normal distribution with U=300 and standard deviation=30. \r<BR>\n" );
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document.write( "A. Find the probability that x assumes as value more than two standard deviations from its mean. More than three standard deviations from U.\r<BR>\n" );
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document.write( "B. Find the probability that x assumes a value within one standard deviation of its mean. Within two standard deviations of U.\r<BR>\n" );
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document.write( "C. Find the value of x that represents the 80th percentile of this distribution. The 10th percentile.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #560417 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=560417\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Using TI or similarly Your Casio fx-115 ES <BR>\n" );
document.write( " A. P(z < -2 or x > 2) = 1- normalcdf(-2,2) = 1 - .9545 = .0455<BR>\n" );
document.write( "P(z < -3 or x >3) = 1- normalcdf(-3,3) = 1 - .9973= .0027<BR>\n" );
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document.write( "B. P( -1 < z < 1) = normalcdf(-1,1) = .6827<BR>\n" );
document.write( "P( -2 < z <2) = normalcdf(-2,2) = .9545\r<BR>\n" );
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