document.write( "Question 923869: Working together, two pumps can drain a certain pool in 3 hours. If it takes the older pump 9 hours to drain the pool by itself, how long will it take the newer pump to drain the pool on its own? \n" ); document.write( "

Algebra.Com's Answer #560404 by TimothyLamb(4379) $\"\"$ $\"About$

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flow rate = r = v/t
\n" ); document.write( "t = v/r
\n" ); document.write( "---
\n" ); document.write( "v = volume of pool
\n" ); document.write( "x = rate of old pump
\n" ); document.write( "y = rate of new pump
\n" ); document.write( "---
\n" ); document.write( "x + y = v/t
\n" ); document.write( "x + y = v/3
\n" ); document.write( "x = v/9
\n" ); document.write( "---
\n" ); document.write( "x + y = v/3
\n" ); document.write( "v/9 + y = v/3
\n" ); document.write( "y = v/3 - v/9
\n" ); document.write( "y = 3v/9 - v/9
\n" ); document.write( "y = 2v/9
\n" ); document.write( "y = (2/2)v/(9/2)
\n" ); document.write( "y = v/(9/2)
\n" ); document.write( "answer:
\n" ); document.write( "(9/2) = 4.5 hours
\n" ); document.write( "---
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