document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=923859>Question 923859</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the point p 4 2 lies on a circle.what is the radius of this circle if the center is located at (-8,-10) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #560391 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=560391\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The point (4,2)lies on a circle.<BR>\n" );
document.write( "If the center is located at (-8,-10). Find the radius.\r<BR>\n" );
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document.write( "Using the distance formula:\r<BR>\n" );
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document.write( "The square root of (x2 - x1)^2 + (y2 - y1)^2<BR>\n" );
document.write( "The square root of (-8 - 4)^2 + (-10 -2)^2<BR>\n" );
document.write( "The square root of 144 + 144<BR>\n" );
document.write( "The square root of 288 = 16.97.\r<BR>\n" );
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document.write( "The radius = 16.97.\r<BR>\n" );
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document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
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