document.write( "Question 78142: Please help me solve this equation. \"lnx+%2B+ln%28x%2B1%29=2\". I tried bringing the foil method bringing \"%28x%2B1%29\" with \"lnx\", but all I ended up with was \"ln+x%5E3=2\" and my teacher said that my steps were wrong. Can you help me to find out where it is exactly I went wrong. \n" ); document.write( "
Algebra.Com's Answer #56035 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You cannot foil these parenthesis, you must use logarithmic identities to solve\r
\n" ); document.write( "\n" ); document.write( "\"lnx+%2B+ln%28x%2B1%29=2\"\r
\n" ); document.write( "\n" ); document.write( "\"ln%28x%2A%28x%2B1%29%29=2\" Use the identity: \"ln%28x%29%2Bln%28y%29=ln%28x%2Ay%29\"\r
\n" ); document.write( "\n" ); document.write( "\"ln%28x%5E2%2Bx%29=2\" Distribute\r
\n" ); document.write( "\n" ); document.write( "\"e%5E%28ln%28x%5E2%2Bx%29%29=e%5E2\" Raise both sides to exponents with the base of e. This undoes the natural log\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bx=e%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bx=e%5E2\" Subtract \"e%5E2\" from both sides\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bx-e%5E2=0\" Since e^2 is approximately 7.3891 we can say\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bx-7.3891=0\"\r
\n" ); document.write( "\n" ); document.write( "Now use the quadratic formula:\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B1x%2B-7.3891+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%281%29%5E2-4%2A1%2A-7.3891=30.5564\".
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\n" ); document.write( " Discriminant d=30.5564 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-1%2B-sqrt%28+30.5564+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%281%29%2Bsqrt%28+30.5564+%29%29%2F2%5C1+=+2.26389218313595\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%281%29-sqrt%28+30.5564+%29%29%2F2%5C1+=+-3.26389218313595\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B1x%2B-7.3891\" can be factored:
\n" ); document.write( " \"1x%5E2%2B1x%2B-7.3891+=+1%28x-2.26389218313595%29%2A%28x--3.26389218313595%29\"
\n" ); document.write( " Again, the answer is: 2.26389218313595, -3.26389218313595.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B1%2Ax%2B-7.3891+%29\"

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\n" ); document.write( "\n" ); document.write( "So our answer is \r
\n" ); document.write( "\n" ); document.write( "\"x=-3.26389218313595\" or \"x=2.26389218313595\"
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