document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=923769>Question 923769</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Are my answers correct for expressing trig in terms of sine and cosine?<BR>\n" );
document.write( "Write in terms of sine and cosine:<BR>\n" );
document.write( "cos^2 &#952;(tan^2 &#952;+1) =?<BR>\n" );
document.write( "cos^2 &#952;+ 1/(cos&#952;)<BR>\n" );
document.write( "= cos^2 &#952;\r<BR>\n" );
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document.write( "(sec &#952;-cos &#952;)/(sin &#952;) = ?<BR>\n" );
document.write( "= (1/(cos&#952;) - 1/(sec&#952;))/(sin&#952;)\r<BR>\n" );
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document.write( "Simplify the trig expression to a power of a single trig function:\r<BR>\n" );
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document.write( "(sec^2 x-1)/(sec^2 x)<BR>\n" );
document.write( "the two sec^2 would cancel and would leave me with -1?\r<BR>\n" );
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document.write( "Are these right?<BR>\n" );
document.write( "Thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #560346 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=560346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write in terms of sine and cosine:<BR>\n" );
document.write( "cos^2(t)(tan^2(t) +1) =?<BR>\n" );
document.write( "= cos^2*(sin^2/cos^2 + 1)<BR>\n" );
document.write( "= sin^2 + cos^2<BR>\n" );
document.write( "= 1<BR>\n" );
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document.write( "Simplify the trig expression to a power of a single trig function:\r<BR>\n" );
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document.write( "(sec^2 x-1)/(sec^2 x)<BR>\n" );
document.write( "= 1 - 1/sec^2<BR>\n" );
document.write( "= 1 - cos^2<BR>\n" );
document.write( "= sin^2<BR>\n" );
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