document.write( "Question 923812: Four equal squares are placed side by side to make a rectangle whose perimeter is 15 meters. Find the area of the rectangle in square meters? ( answer is 9 - show your solution ) \n" ); document.write( "
Algebra.Com's Answer #560328 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Perimeter of a rectangle(P)equals two times Length(L) plus two times Width(W) or P=2L+2W \n" ); document.write( "Let S=length of the side of the squares \n" ); document.write( "Then the length of the rectangle is 4S \n" ); document.write( "And the width of the rectangle is S \n" ); document.write( "Sooo \n" ); document.write( "Perimeter of rectangle=15 meters=2(4S)+2S or \n" ); document.write( "8S+2S=15 \n" ); document.write( "10S=15 \n" ); document.write( "S=15/10=(3/2) meters \n" ); document.write( "Area of rectangle(A)=Length(L) times Width(W) or A=LW \n" ); document.write( "Length of rectangle=4(3/2)=6 meters \n" ); document.write( "Width of rectangle=3/2 meters \n" ); document.write( "Area of of rectangle(A)=6*(3/2)=9 sq meters\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |