document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=923797>Question 923797</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi looking to figure out how to find the 83rd term, of arithmetic sequence with first term being 6 and common difference -1/2\r<BR>\n" );
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document.write( "Please help me,  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #560325 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=560325\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Arithmetic sequence =><BR>\n" );
document.write( "x(n) = a + d(n - 1)<BR>\n" );
document.write( "a = 6<BR>\n" );
document.write( "d = -1/2<BR>\n" );
document.write( "x(83) = 6 + -1/2(83 - 1)<BR>\n" );
document.write( "= -35<BR>\n" );
document.write( "Hope this helps<BR>\n" );
document.write( ":-) </SPAN>\n" );
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