document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=923802>Question 923802</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A photograph is 16 inches wide and 9 inches long and is surrounded by a frame of uniform width x. If the area of the frame is 84 square inches, find the uniform width of the frame.\r<BR>\n" );
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document.write( "a. What is the area of the photograph and frame?<BR>\n" );
document.write( "b. Given the area of the frame which is 84 square inches, formulate the relationship among three areas and simplify.\r<BR>\n" );
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document.write( "I'm not sure about letter b but is the equation a(w)= (16+2x)(9+2x) or a(w)= 4x^2+25x+144 correct?<BR>\n" );
document.write( "And I'm not sure if I should just add the two areas for letter 'a' or the area given for the frame is just the area of its borders/sides with the portion of the picture cut out. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #560320 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=560320\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Dimensions of picture, 16 and 9 inches.\r<BR>\n" );
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document.write( "Area of the picture, 16*9.<BR>\n" );
document.write( "Area of picture AND frame, (16+2x)(9+2x).<BR>\n" );
document.write( "Area of just the franem 84 sq.inchs.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28%2816%2B2x%29%289%2B2x%29-16%2A9=84%29 ALIGN=MIDDLE  ALT=\"highlight_green%28%2816%2B2x%29%289%2B2x%29-16%2A9=84%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, meaning the difference in area between the picture&frame combination and the picture will equal the area of the frame by itself.\r<BR>\n" );
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document.write( "That is a formulation among the known values and the unknown width of the frame; but was not any attempt at formulating a function.  Still, you can solve for x, the uniform frame width.\r<BR>\n" );
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document.write( "Simplification is producing <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x%5E2%2B25x-720=0 ALIGN=MIDDLE  ALT=\"3x%5E2%2B25x-720=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  \r<BR>\n" );
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document.write( "Applying the general solution of a quadratic equation and taking only the PLUS square root form,  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28x=%28-25%2Bsqrt%289265%29%29%2F6%29 ALIGN=MIDDLE  ALT=\"highlight%28x=%28-25%2Bsqrt%289265%29%29%2F6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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