document.write( "Question 78139: Find the vertex and intercepts for the parabola. Sketch the graph.\r
\n" ); document.write( "\n" ); document.write( "g(x)=x^2+x-6
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Algebra.Com's Answer #56032 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
To find the vertex, lets complete the square and put the equation in vertex form:\r
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Solved by pluggable solver: Completing the Square to Get a Quadratic into Vertex Form

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\n" ); document.write( " \"y=1+x%5E2%2B1+x-6\" Start with the given equation
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\n" ); document.write( " \"y%2B6=1+x%5E2%2B1+x\" Add \"6\" to both sides
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\n" ); document.write( " \"y%2B6=1%28x%5E2%2B1x%29\" Factor out the leading coefficient \"1\"
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\n" ); document.write( " Take half of the x coefficient \"1\" to get \"1%2F2\" (ie \"%281%2F2%29%281%29=1%2F2\").
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\n" ); document.write( " Now square \"1%2F2\" to get \"1%2F4\" (ie \"%281%2F2%29%5E2=%281%2F2%29%281%2F2%29=1%2F4\")
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\n" ); document.write( " \"y%2B6=1%28x%5E2%2B1x%2B1%2F4-1%2F4%29\" Now add and subtract this value inside the parenthesis. Doing both the addition and subtraction of \"1%2F4\" does not change the equation
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\n" ); document.write( " \"y%2B6=1%28%28x%2B1%2F2%29%5E2-1%2F4%29\" Now factor \"x%5E2%2B1x%2B1%2F4\" to get \"%28x%2B1%2F2%29%5E2\"
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\n" ); document.write( " \"y%2B6=1%28x%2B1%2F2%29%5E2-1%281%2F4%29\" Distribute
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\n" ); document.write( " \"y%2B6=1%28x%2B1%2F2%29%5E2-1%2F4\" Multiply
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\n" ); document.write( " \"y=1%28x%2B1%2F2%29%5E2-1%2F4-6\" Now add \"%2B6\" to both sides to isolate y
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\n" ); document.write( " \"y=1%28x%2B1%2F2%29%5E2-25%2F4\" Combine like terms
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\n" ); document.write( " Now the quadratic is in vertex form \"y=a%28x-h%29%5E2%2Bk\" where \"a=1\", \"h=-1%2F2\", and \"k=-25%2F4\". Remember (h,k) is the vertex and \"a\" is the stretch/compression factor.
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\n" ); document.write( " Check:
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\n" ); document.write( " Notice if we graph the original equation \"y=1x%5E2%2B1x-6\" we get:
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\n" ); document.write( " \"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C1x%5E2%2B1x-6%29\" Graph of \"y=1x%5E2%2B1x-6\". Notice how the vertex is (\"-1%2F2\",\"-25%2F4\").
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\n" ); document.write( " Notice if we graph the final equation \"y=1%28x%2B1%2F2%29%5E2-25%2F4\" we get:
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\n" ); document.write( " \"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C1%28x%2B1%2F2%29%5E2-25%2F4%29\" Graph of \"y=1%28x%2B1%2F2%29%5E2-25%2F4\". Notice how the vertex is also (\"-1%2F2\",\"-25%2F4\").
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\n" ); document.write( " So if these two equations were graphed on the same coordinate plane, one would overlap another perfectly. So this visually verifies our answer.
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\n" ); document.write( "\n" ); document.write( "So the vertex is:\r
\n" ); document.write( "\n" ); document.write( "(-0.5, -6.25)\r
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\n" ); document.write( "\n" ); document.write( "Now lets find the intercepts. The easiest way is to use the quadratic formula:\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B1x%2B-6+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%281%29%5E2-4%2A1%2A-6=25\".
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\n" ); document.write( " Discriminant d=25 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-1%2B-sqrt%28+25+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%281%29%2Bsqrt%28+25+%29%29%2F2%5C1+=+2\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%281%29-sqrt%28+25+%29%29%2F2%5C1+=+-3\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B1x%2B-6\" can be factored:
\n" ); document.write( " \"1x%5E2%2B1x%2B-6+=+1%28x-2%29%2A%28x--3%29\"
\n" ); document.write( " Again, the answer is: 2, -3.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B1%2Ax%2B-6+%29\"

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\n" ); document.write( "\n" ); document.write( "So the x-intercepts are x=2, x=-3\r
\n" ); document.write( "\n" ); document.write( "And here's the graph\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+x%5E2%2Bx-6%29+\" graph of \"y=x%5E2%2Bx-6\"
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