document.write( "Question 78127: Find all real or imaginary solutions to each equation. Use the method of your choice.\r
\n" ); document.write( "\n" ); document.write( "w^2=-225\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "3v^2+4v-1=0
\n" ); document.write( "

Algebra.Com's Answer #56031 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
For each of these problems it's easiest to use the quadratic formula (since there are going to be complex roots):\r
\n" ); document.write( "\n" ); document.write( "\"w%5E2=-225\"\r
\n" ); document.write( "\n" ); document.write( "\"w%5E2%2B225=0\" Add 225 to both sides\r
\n" ); document.write( "\n" ); document.write( "Now lets use the quadratic formula:\r
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aw%5E2%2Bbw%2Bc=0\" (in our case \"1w%5E2%2B0w%2B225+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"w%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%280%29%5E2-4%2A1%2A225=-900\".
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\n" ); document.write( " The discriminant -900 is less than zero. That means that there are no solutions among real numbers.

\n" ); document.write( " If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

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\n" ); document.write( " In the field of imaginary numbers, the square root of -900 is + or - \"sqrt%28+900%29+=+30\".
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\n" ); document.write( " The solution is \"w%5B12%5D+=+%28-0%2B-+i%2Asqrt%28+-900+%29%29%2F2%5C1+=++%28-0%2B-+i%2A30%29%2F2%5C1+\"
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\n" ); document.write( " Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B0%2Ax%2B225+%29\"

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\n" ); document.write( "\n" ); document.write( "So we have 2 complex (or imaginary) solutions:\r
\n" ); document.write( "\n" ); document.write( "\"x=15i\" or \"x=-15i\"\r
\n" ); document.write( "\n" ); document.write( "------------------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "Again lets use the quadratic formula:\r
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"av%5E2%2Bbv%2Bc=0\" (in our case \"3v%5E2%2B4v%2B-1+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"v%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
\n" ); document.write( "
\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
\n" ); document.write( "
\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%284%29%5E2-4%2A3%2A-1=28\".
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\n" ); document.write( " Discriminant d=28 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-4%2B-sqrt%28+28+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"v%5B1%5D+=+%28-%284%29%2Bsqrt%28+28+%29%29%2F2%5C3+=+0.21525043702153\"
\n" ); document.write( " \"v%5B2%5D+=+%28-%284%29-sqrt%28+28+%29%29%2F2%5C3+=+-1.54858377035486\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"3v%5E2%2B4v%2B-1\" can be factored:
\n" ); document.write( " \"3v%5E2%2B4v%2B-1+=+3%28v-0.21525043702153%29%2A%28v--1.54858377035486%29\"
\n" ); document.write( " Again, the answer is: 0.21525043702153, -1.54858377035486.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B4%2Ax%2B-1+%29\"

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\n" ); document.write( "\n" ); document.write( "So we have 2 real solutions:\r
\n" ); document.write( "\n" ); document.write( "\"x=-1.54858377035486\" or \"x=0.21525043702153\"
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