document.write( "Question 923723: Write in terms of sine and cosine:\r
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document.write( "cos^2 θ(tan^2 θ+1) = \r
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document.write( "(secθ-cosθ)/(sinθ) = \r
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document.write( "Simplify the trig expression to a power of a single trig function:\r
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document.write( "(sec^2x-1)/(sec^2x)\r
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document.write( "Please be descriptive on how these are solved\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #560300 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Write in terms of sine and cosine: \n" ); document.write( "cos^2 θ(tan^2 θ+1) = cos^2*sec^2 = 1 \n" ); document.write( "--------------------- \n" ); document.write( "(secθ-cosθ)/(sinθ) = ((/cos)-cos)/sin = ((1-cos^2)/cos) / sin \n" ); document.write( "--- \n" ); document.write( "= (sin^2/cos)/sin = sin/cos = tan(theta) \n" ); document.write( "------------------------------------------------ \n" ); document.write( "----------------------------------------------------- \n" ); document.write( " Simplify the trig expression to a power of a single trig function: \n" ); document.write( "(sec^2x-1)/(sec^2x) = (1 - (1/sec^2(x)) = (1-cos^2(x)) = sin^2(x) \n" ); document.write( "================================== \n" ); document.write( "Please be descriptive on how these are solved \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------- \n" ); document.write( " \n" ); document.write( " |