document.write( "Question 923734: Two candles of the same height are lit at the same time. One burns down in 5 hours while the other burns down in 3 hours. After how many hours will the first candle be three times the height of the second? \n" ); document.write( "
Algebra.Com's Answer #560297 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Two candles of the same height are lit at the same time. One burns down in 5 hours while the other burns down in 3 hours. \n" ); document.write( ": \n" ); document.write( "lets assume both candles start out at 15\" high \n" ); document.write( "then \n" ); document.write( "the 1st candle burns 3\" per hr \n" ); document.write( "and \n" ); document.write( "the 2nd candle burns 5\" per hr \n" ); document.write( ": \n" ); document.write( "\" After how many hours will the first candle be three times the height of the second? \n" ); document.write( "let t = time in hrs for this to be true \n" ); document.write( "12 - 3t = 3(12-5t) \n" ); document.write( "12 - 3t = 36 - 15t \n" ); document.write( "-3t + 15t = 36 - 12 \n" ); document.write( "12t = 24 \n" ); document.write( "t = 24/12 \n" ); document.write( "t = 2 hrs \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "see if this is true \n" ); document.write( "12 - 3(2) = 6\" \n" ); document.write( "12 - 5(2) = 2\" \n" ); document.write( " |