document.write( "Question 923726: \"+Let+f+%28x%29+=+1%2Fx%5E2+%28sqrt%2825+%2B+x%5E2%29%29+\" \"+and+g%28t%29+=+5+tan%28t%29+for+0+%3C+t+%3C+pi%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "Find (f º g)(t) and simplify so that there are no radicals in the function. Write your answer in terms of sin(t) and cos(t).\r
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\n" ); document.write( "\n" ); document.write( "There shouldn't be a parentheses around 25+x^2 just couldn't make it without one it seems
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\n" ); document.write( "\n" ); document.write( "\"+Let+f+%28x%29+=+4x%2F%28sqrt%281-x%5E2%29%29+\" \"+and+g%28t%29+=+sin%28t%29+for+0+%3C+t+%3C+pi%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "Find (f compose g)(t) and simplify. Write your answer in terms of sin t and cos t.\r
\n" ); document.write( "\n" ); document.write( "(f º g)(t) =\r
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Algebra.Com's Answer #560277 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first one to get you started\r
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\n" ); document.write( "\n" ); document.write( "(f º g)(t) is the same as \"f%28g%28t%29%29\". They are just two ways of saying the same exact thing.\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+1%2F%28x%5E2%2Asqrt%2825+%2B+x%5E2%29%29+\" Start with f(x)\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28t%29%29+=+1%2F%28%28g%28t%29%29%5E2%2Asqrt%2825+%2B+%28g%28t%29%29%5E2%29%29+\" Replace every x with g(t)\r
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\n" ); document.write( "\n" ); document.write( " On the right side, replace all copies of g(t) with 5tan(t)\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28t%29%29+=+1%2F%2825%2Atan%5E2%28t%29%2Asqrt%2825+%2B+25%2Atan%5E2%28t%29%29%29+\" Square \"5%2Atan%28t%29\" to get \"25%2Atan%5E2%28t%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28t%29%29+=+1%2F%2825%2Atan%5E2%28t%29%2Asqrt%2825%281+%2B+tan%5E2%28t%29%29%29%29+\" Factor\r
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\n" ); document.write( "\n" ); document.write( " Break up the root\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28t%29%29+=+1%2F%2825%2Atan%5E2%28t%29%2A5%2Asqrt%281+%2B+tan%5E2%28t%29%29%29+\" Take the square root of 25\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28t%29%29+=+1%2F%2825%2Atan%5E2%28t%29%2A5%2Asqrt%28sec%5E2%28t%29%29%29+\" Use the trig identity \"1%2Btan%5E2%28t%29+=+sec%5E2%28t%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28t%29%29+=+1%2F%2825%2Atan%5E2%28t%29%2A5%2Asec%28t%29%29+\" Take the square root of \"sec%5E2%28t%29\". Since \"0+%3C+t+%3C+pi%2F2\", this means \"sec%28t%29\" is positive.\r
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\n" ); document.write( "\n" ); document.write( " Rewrite tan & sec in terms of sine & cosine.\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28t%29%29+=+1%2F%28%28125%2Asin%5E2%28t%29%29%2F%28cos%5E3%28t%29%29%29+\" Multiply and rearrange terms.\r
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\n" ); document.write( "\n" ); document.write( "\"f%28g%28t%29%29+=+%28cos%5E3%28t%29%29%2F%28125%2Asin%5E2%28t%29%29+\" Flip the fraction (1/[a/b] = b/a)\r
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\n" ); document.write( "\n" ); document.write( "Side Note: this only works when \"sec%28t%29+%3E+0\" (in quadrant I and IV)\r
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\n" ); document.write( "\n" ); document.write( "Let me know if that helps or not. Thanks.\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, feel free to email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "My Website: http://www.freewebs.com/jimthompson5910/home.html
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