document.write( "Question 923675: Solving log(x^2-15)=1\r
\n" ); document.write( "\n" ); document.write( "Do not know how to solve for this. The answer is +or- 5, but don't know how to get that answer.
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Algebra.Com's Answer #560242 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"log%28x%5E2-15%29=1\" ...you have log base \"10\", then we can write \"1\" as \"log%2810%29\" because \"log%2810%2C10%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28x%5E2-15%29=log%2810%29\" ...if log same, then \"x%5E2-15=10\" is same too\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-15=10\"...solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2=10%2B15\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2=25\"\r
\n" ); document.write( "\n" ); document.write( "\"x=sqrt%2825%29\"\r
\n" ); document.write( "\n" ); document.write( "so, \"x=5\" or \"x=-5\"
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