document.write( "Question 923637: Suppose sin x = 1/7
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document.write( "cos x > 0, sin y = −2/5
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document.write( "and cos y < 0. Then
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document.write( "cos x =
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document.write( "cos y =
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document.write( "Find each of the following quantities:
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document.write( "sin(x + y) =
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document.write( "cos(x + y) =
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document.write( "tan(x + y) = \n" );
document.write( "
Algebra.Com's Answer #560192 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Suppose sin x = 1/7 cos x > 0, \n" ); document.write( "Note: cos(x) = sqrt(49-1)/7 = sqrt(48)/7 \n" ); document.write( "----------------------------------------------- \n" ); document.write( "sin y = −2/5 and cos y < 0. \n" ); document.write( "Note: cos(y) = -sqrt(25-4)/5 = -sqrt(21)/5 \n" ); document.write( "------------------------------ \n" ); document.write( "Then \n" ); document.write( "cos x = 4sqrt(3)/7 \n" ); document.write( "cos y = -sqrt(21)/5 \n" ); document.write( "---------------------------- \n" ); document.write( "Find each of the following quantities: \n" ); document.write( "sin(x + y) = sin(x)cos(y)+cos(x)sin(y) \n" ); document.write( "Substitute to get the numerical answer. \n" ); document.write( "----- \n" ); document.write( "cos(x + y) = cos(x)cos(y)-sin(x)sin(y) \n" ); document.write( "Substitute:: \n" ); document.write( "tan(x + y) = \n" ); document.write( "Divide sin(x+y) by cos(x+y) \n" ); document.write( "================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( " |