document.write( "Question 923632: Suppose sin x = 1/7
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document.write( "cos x > 0, sin y = −2/5
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document.write( "and cos y < 0. Then
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document.write( "cos x =
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document.write( "cos y =
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document.write( "Find each of the following quantities:
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document.write( "sin(x + y) =
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document.write( "cos(x + y) =
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document.write( "tan(x + y) = \n" );
document.write( "
Algebra.Com's Answer #560186 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! sin x = 1/7, cos x > 0, cos x = 4√3 /7 \n" ); document.write( "....... \n" ); document.write( " sin y = −2/5, and cos y < 0, cosy = √21 / 5 \n" ); document.write( "........Plug and Play \n" ); document.write( "sin(x + y) = sin x cos y + sin y cos x \n" ); document.write( "sin(x + y) = (1/7)(√21 /5) + (-2/5)(4√3 /7) \n" ); document.write( " |