document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=923628>Question 923628</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The half life of Iron-55 is approximately 2.7 years. How much of a 5 gram sample of Iron-55 would remain after 6 years? Round to 3 decimal places.\r<BR>\n" );
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document.write( "Answer to part 1: a=0.773584 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #560180 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=560180\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Q%5Bt%5D+=+Q%5B0%5D+e%5E%28-kt%29++ ALIGN=MIDDLE  ALT=\"Q%5Bt%5D+=+Q%5B0%5D+e%5E%28-kt%29++\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".5 = e^(-2.7k)<BR>\n" );
document.write( "ln(.5)/-2.7) = .2567<BR>\n" );
document.write( "........<BR>\n" );
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