document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=923573>Question 923573</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use substitution to solve for x and y. 3x+y=-14    and    -2x-y=9\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Use substitution to solve for x and y.   y=1/2x+5   and    y=-5/2x-1\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Use  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #560178 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=560178\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use substitution to solve for x and y. <BR>\n" );
document.write( "3x+y=-14 --> y = -3x - 14<BR>\n" );
document.write( "Sub for y in the 2nd eqn<BR>\n" );
document.write( "-2x-y=9<BR>\n" );
document.write( "-2x - (-3x-14) = 9<BR>\n" );
document.write( "-2x + 3x + 14 = 9<BR>\n" );
document.write( "y = -5<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "-2x-y=9<BR>\n" );
document.write( "-2x + 5 = 9<BR>\n" );
document.write( "-2x = 4<BR>\n" );
document.write( "x = -2<BR>\n" );
document.write( "============<BR>\n" );
document.write( "Use substitution to solve for x and y.   <BR>\n" );
document.write( "y=1/2x+5<BR>\n" );
document.write( "y=-5/2x-1<BR>\n" );
document.write( "Since both right sides = y,\r<BR>\n" );
document.write( "\n" );
document.write( "1/2x+5 = -5/2x-1<BR>\n" );
document.write( "x+10 = -5x-2<BR>\n" );
document.write( "etc\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );