document.write( "Question 923616: A car worth $12000, is purchased at the beginning of 2013, with a deposit of $2000. The remainder is borrowed from the bank, with interest compounding annually, and paid off in monthly instalments of $349.92, until the end of 2015.
\n" ); document.write( "What was the annual compound interest rate from the bank?\r
\n" ); document.write( "\n" ); document.write( "I got 1.71%.
\n" ); document.write( "Can anyone please help me work out the solution for this question?? :(
\n" ); document.write( "All your answers will be appreciated
\n" ); document.write( "thank you
\n" ); document.write( "

Algebra.Com's Answer #560160 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
In General \"A%28t%29+=+P%281%2Br%2Fn%29%5E%28nt%29\"
\n" ); document.write( "A = Accumulated Amount \"36+%2A+349.92\"
\n" ); document.write( "P= principal = 10,000
\n" ); document.write( "r= annual rate = .
\n" ); document.write( "n= periods per year = 1
\n" ); document.write( "t= years = 3
\n" ); document.write( "\"A%2FP+=+%281%2Br%29%5E%283%29\"
\n" ); document.write( "\"root%283%2C+12594.40%2F10000%29\" - 1 = r = .08 0r 8% interest
\n" ); document.write( "
\n" ); document.write( "
\n" );