document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=923523>Question 923523</A>: <I><SPAN STYLE=\"word-break: break-all;\"> we need to solve for x and y\r<BR>\n" );
document.write( "\n" );
document.write( "the sum of 3 times the first number and twice the second number is 43.  if the second number is subtracted from twice the first number the result is negative 4.  Find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #560132 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=560132\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x + 2y = 43   <BR>\n" );
document.write( "<u>2(2x - y = -4</u><BR>\n" );
document.write( "7x = 35<BR>\n" );
document.write( "x = 5  and y = 14  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2A5+%2B+4 ALIGN=MIDDLE  ALT=\"2%2A5+%2B+4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and...checking<BR>\n" );
document.write( "3x + 2y = 43 <BR>\n" );
document.write( "15 + 28 = 43<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );