document.write( "Question 923568: Create bell curve for coffee shop franchise if average price of coffee cup is two dollars with standard deviations of fifty cent. Use bell curve the following Part A percentage of coffee sold within one standard deviation from mean Part B percentage of coffee sold between fours dollars and five dollars Part c if approximately, 200 cups were sold on given day, how many cups were sold between prices ranging $1.50 to $3.50. \n" ); document.write( "

Algebra.Com's Answer #560121 by ewatrrr(24785) $\"\"$ $\"About$

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mean = $2, sd = $0.50
\n" ); document.write( "A. Empirical rule: one standard deviation from the mean accounts for about 68% of the set
\n" ); document.write( ".......
\n" ); document.write( "b. P( $4 < x < $5) = normalcdf(4,5,2,.50) = .00003 0r .003%
\n" ); document.write( ".......
\n" ); document.write( "C. P( $1.50 < x < $3.50)
\n" ); document.write( " $\"z+=blue+%28x+-+mu%29%2Fblue%28sigma%2Fsqrt%28n%29%29\"$
\n" ); document.write( "z = -.50/(.50 = -1 and z = 1.50/.50 = 3
\n" ); document.write( " P( $1.50 < x < $3.50) = normalcdf(-1, 3) = .84 0r 84%
\n" ); document.write( "0r
\n" ); document.write( " P( $1.50 < x < $3.50) = P(z ≤ 3) - P( z ≤ - 1) = .9987 - .1587 = .84 0r 84% \n" ); document.write( "

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