document.write( "Question 923400: the height of an open box is 1 cm more than the length of a side of its square base. if the open box has a surface area of 96 cm^2, find the dimensions \n" ); document.write( "

Algebra.Com's Answer #560050 by josgarithmetic(39617) $\"\"$ $\"About$

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h, height
\n" ); document.write( "x, length of edge of square base
\n" ); document.write( "h=1+x, $\"h=x%2B1\"$ \r
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\n" ); document.write( "\n" ); document.write( "The area of all the surfaces is $\"4%28hx%29%2Bx%5E2=4%28x%2B1%29x%2Bx%5E2\"$ ; and the amount of this area is given:\r
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\n" ); document.write( "\n" ); document.write( " $\"highlight_green%284x%28x%2B1%29%2Bx%5E2=96%29\"$ .\r
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\n" ); document.write( "\n" ); document.write( "STEPS
\n" ); document.write( " $\"4x%5E2%2B4x%2Bx%5E2-96=0\"$
\n" ); document.write( " $\"5x%5E2%2B4x-96=0\"$
\n" ); document.write( "Discrm, 16+4*5*96=16+20*96=1936=44^2
\n" ); document.write( " $\"x=%28-4%2B-+44%29%2F%282%2A5%29\"$
\n" ); document.write( " $\"x=40%2F10\"$
\n" ); document.write( " $\"highlight%28x=4%29\"$ and this means $\"highlight%28h=5%29\"$ . \n" ); document.write( "

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