document.write( "Question 923463: Can you please help me solve this? I think I got the answer, but I am not sure.\r
\n" ); document.write( "\n" ); document.write( "e^(x^2)=e^(x) * e^(6)\r
\n" ); document.write( "\n" ); document.write( "I multiplied (e^x and e^6, which meant adding the exponents)\r
\n" ); document.write( "\n" ); document.write( "e^(x^2)= e^(x+6)\r
\n" ); document.write( "\n" ); document.write( "Then got rid of the base e on both sides\r
\n" ); document.write( "\n" ); document.write( "x^2=x+6\r
\n" ); document.write( "\n" ); document.write( "(-x^2)+x+6=0\r
\n" ); document.write( "\n" ); document.write( "x=-2 x=3
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Algebra.Com's Answer #560045 by josgarithmetic(39625)\"\" \"About 
You can put this solution on YOUR website!
The solution process and answer result are good.\r
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\n" ); document.write( "\n" ); document.write( "A couple of formal differences could be made in place.\r
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\n" ); document.write( "\n" ); document.write( "You would \"take the log_base_e of both sides\" at \"e%5E%28x%5E2%29=+e%5E%28x%2B6%29\"
\n" ); document.write( "\"ln%28e%5E%28x%5E2%29%29=ln%28e%5E%28x%2B6%29%29\"
\n" ); document.write( "\"%28x%5E2%29ln%28e%29=%28x%2B6%29%2Aln%28e%29\"
\n" ); document.write( "\"x%5E2=x%2B6\"\r
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\n" ); document.write( "\n" ); document.write( "The next step will give a more convenient form to work with,
\n" ); document.write( "\"x%5E2=x%2B6\"
\n" ); document.write( "\"x%5E2-x-6=x%2B6-x-6\"
\n" ); document.write( "\"x%5E2-x-6=0\"\r
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\n" ); document.write( "\n" ); document.write( "Easy enough to factor,
\n" ); document.write( "\"%28x%2B2%29%28x-3%29=0\"
\n" ); document.write( "Which give the solutions you found.
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