document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=923355>Question 923355</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car leaves town at 72 km/hr. An hour later, a second car leaves the same town, on the same road, traveling at 90 km/hr. In how many hours will the second car catch up to the first? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #559990 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=559990\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D = rt, Distances Equal<BR>\n" );
document.write( "72t = 90(t-1)<BR>\n" );
document.write( "90 = 18t<BR>\n" );
document.write( "90/18 = t = 5hr<BR>\n" );
document.write( " second car catch up to the first in 4hrs </SPAN>\n" );
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