document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=923299>Question 923299</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Is this right? please check exact value of tan(5&#960;/3)sec(-5&#960;/6) and other?\r<BR>\n" );
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document.write( "Find the exact value of: \r<BR>\n" );
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document.write( "tan(5&#960;/3)sec(-5&#960;/6) \r<BR>\n" );
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document.write( "sin(27&#960;/4)cos(1043&#960;) \r<BR>\n" );
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document.write( "I think is I must find must the coterminal point then use trig identity to solve. therefore \r<BR>\n" );
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document.write( "5&#960;/3+2&#960;/1 = 11&#960;/3 <BR>\n" );
document.write( "tan = x/y but 11&#960;/3 I dont see with my unit circle? so not sure \r<BR>\n" );
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document.write( "sec(-5&#960;/6) <BR>\n" );
document.write( "-5&#960;/6+2&#960;/1 = 7&#960;/6 <BR>\n" );
document.write( "sec = 1/x = -2/&#8730;(3) \r<BR>\n" );
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document.write( "sin(27&#960;/4) I think for this I must subtract 2&#960; and therefore <BR>\n" );
document.write( "27&#960;/4-2&#960;/1 <BR>\n" );
document.write( "27&#960;/4-8&#960;/4 <BR>\n" );
document.write( "=3&#960;/4 <BR>\n" );
document.write( "sin =y/r <BR>\n" );
document.write( "=(&#8730;2/2) \r<BR>\n" );
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document.write( "cos(1043&#960;) <BR>\n" );
document.write( "I know there is some trick with this but I forget it. I think I have to break up? \r<BR>\n" );
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document.write( "Please help <BR>\n" );
document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #559953 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=559953\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Is this right? please check exact value of tan(5&#960;/3)sec(-5&#960;/6) and other? <BR>\n" );
document.write( " Find the exact value of: <BR>\n" );
document.write( " tan(5&#960;/3)sec(-5&#960;/6) <BR>\n" );
document.write( " sin(27&#960;/4)cos(1043&#960;) \r<BR>\n" );
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document.write( "I think is I must find must the coterminal point then use trig identity to solve. therefore <BR>\n" );
document.write( " 5&#960;/3+2&#960;/1 = 11&#960;/3 ***********  There's no reason to add 2pi.<BR>\n" );
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document.write( "You can just use a calculator.  You might change -5pi/6 to 7pi/6, but it's not necessary with a calculator.<BR>\n" );
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document.write( " tan = x/y but 11&#960;/3 I dont see with my unit circle? so not sure <BR>\n" );
document.write( "Don't add 2pi.  5pi/3 is on the unit circle (= 300 degs)<BR>\n" );
document.write( " sec(-5&#960;/6) <BR>\n" );
document.write( " -5&#960;/6+2&#960;/1 = 7&#960;/6 <BR>\n" );
document.write( " sec = 1/x = -2/&#8730;(3) **** sec = 1/cos, not 1/x, but it is -2/sqrt(3)<BR>\n" );
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document.write( " sin(27&#960;/4) I think for this I must subtract 2&#960; and therefore <BR>\n" );
document.write( " 27&#960;/4-2&#960;/1 <BR>\n" );
document.write( " 27&#960;/4-8&#960;/4 <BR>\n" );
document.write( " =3&#960;/4 (subtracting 2pi twice --> sin(3pi/4)<BR>\n" );
document.write( " sin =y/r <BR>\n" );
document.write( " =(&#8730;2/2)<BR>\n" );
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document.write( " cos(1043&#960;)<BR>\n" );
document.write( "= cos(521*(2pi) + pi)<BR>\n" );
document.write( "= cos(pi)<BR>\n" );
document.write( "= -1 </SPAN>\n" );
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