document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=923206>Question 923206</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem.\r<BR>\n" );
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document.write( "The width of a rug is 7 feet less than one-half it's length. Find the dimensions of the rug if the area is 60 square feet. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #559908 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=559908\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The width of a rug is 7 feet less than one-half it's length. Find the dimensions of the rug if the area is 60 square feet.<BR>\n" );
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document.write( "Let the length be \"L\"::<BR>\n" );
document.write( "Then the width is (1/2)L - 7<BR>\n" );
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document.write( "Equation to solve for \"L\"::<BR>\n" );
document.write( "Area = length*width<BR>\n" );
document.write( "60 = L((1/2)L - 7)<BR>\n" );
document.write( "60 = (1/2)L^2 - 7L)<BR>\n" );
document.write( "120 = L^2 - 14L<BR>\n" );
document.write( "Rearrange::<BR>\n" );
document.write( "L^2 - 14L - 120 = 0<BR>\n" );
document.write( "(L-20)(L+6) = 0<BR>\n" );
document.write( "Positive solution::<BR>\n" );
document.write( "Length = 20 ft<BR>\n" );
document.write( "Width = (1/2)L - 7 = 3 ft.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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