document.write( "Question 923156: without using cocept of inverse of a matrix , solve the following matrix equation:
\n" ); document.write( "5 4 x=1 -2
\n" ); document.write( "1 1 1 3
\n" ); document.write( "where x is a 2×2 matrix.
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Algebra.Com's Answer #559894 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Let
\n" ); document.write( "\"x=%28matrix%282%2C2%2Ca%2Cb%2Cc%2Cd%29%29\"
\n" ); document.write( "Then,
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\n" ); document.write( "Looking at each element,
\n" ); document.write( "1.\"5a%2B4c=1\"
\n" ); document.write( "2.\"5b%2B4d=-2\"
\n" ); document.write( "3.\"a%2Bc=1\"
\n" ); document.write( "4.\"b%2Bd=3\"
\n" ); document.write( "From eq. 3,
\n" ); document.write( "\"a=1-c\"
\n" ); document.write( "From eq. 4,
\n" ); document.write( "\"b=3-d\"
\n" ); document.write( "Substitute in eq. 1 and 2,
\n" ); document.write( "\"5%281-c%29%2B4c=1\"
\n" ); document.write( "\"5-5c%2B4c=1\"
\n" ); document.write( "\"5-c=1\"
\n" ); document.write( "\"c=4\"
\n" ); document.write( "Then,
\n" ); document.write( "\"a=1-4=-3\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"5%283-d%29%2B4d=-2\"
\n" ); document.write( "\"15-5d%2B4d=-2\"
\n" ); document.write( "\"15-d=-2\"
\n" ); document.write( "\"-d=-17\"
\n" ); document.write( "\"d=17\"
\n" ); document.write( "Then,
\n" ); document.write( "\"b=3-17=-14\"
\n" ); document.write( "So then,
\n" ); document.write( "\"x=%28matrix%282%2C2%2C-3%2C-14%2C4%2C17%29%29\"\r
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