document.write( "Question 923081: solve this problem using elimination substitution and graphing
\n" ); document.write( " 1)p+3q=16
\n" ); document.write( " p+q=6
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Algebra.Com's Answer #559863 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
Elimination/Addition\r
\n" ); document.write( "\n" ); document.write( "\"p%2B3q=16\".......eq.1
\n" ); document.write( "\"p%2Bq=6+\".........eq.2
\n" ); document.write( "____________subtract 2 from 1\r
\n" ); document.write( "\n" ); document.write( "\"p%2B3q-%28p%2Bq%29=16-6\"\r
\n" ); document.write( "\n" ); document.write( "\"cross%28p%29%2B3q-cross%28p%29-q=10\"\r
\n" ); document.write( "\n" ); document.write( "\"3q-q=10\"\r
\n" ); document.write( "\n" ); document.write( "\"2q=10\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28q=5%29\"\r
\n" ); document.write( "\n" ); document.write( "go to \"p%2Bq=6+\".........eq.2, plug in \"5\" for \"q\"\r
\n" ); document.write( "\n" ); document.write( "\"p%2B5=6+\"\r
\n" ); document.write( "\n" ); document.write( "\"p=6-5+\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28p=1%29+\"\r
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\n" ); document.write( "\n" ); document.write( "by SUBSTITUTION\r
\n" ); document.write( "\n" ); document.write( "\"p%2B3q=16\".......eq.1
\n" ); document.write( "\"p%2Bq=6+\".........eq.2
\n" ); document.write( "____________\r
\n" ); document.write( "\n" ); document.write( "\"p%2B3q=16\".......eq.1..solve for \"p\"\r
\n" ); document.write( "\n" ); document.write( "\"p=16-3q\"...substitute in 2 \r
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\n" ); document.write( "\n" ); document.write( "\"16-3q%2Bq=6+\".........eq.2..solve for \"q\"\r
\n" ); document.write( "\n" ); document.write( "\"-2q=6-16+\"\r
\n" ); document.write( "\n" ); document.write( "\"-2q=-10+\" ...both sides multiply by \"-1\"\r
\n" ); document.write( "\n" ); document.write( "\"2q=10+\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28q=5%29+\"....substitute in eq.1\r
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\n" ); document.write( "\n" ); document.write( "\"p%2B3%2A5=16\".......eq.1\r
\n" ); document.write( "\n" ); document.write( "\"p%2B15=16\"\r
\n" ); document.write( "\n" ); document.write( "\"p=16-15\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28p=1%29\"\r
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\n" ); document.write( "\n" ); document.write( "by Graphing\r
\n" ); document.write( "\n" ); document.write( "In order to graph these equations, we need to solve for q for each equation.\r
\n" ); document.write( "\n" ); document.write( "\"p%2B3q=16\".......eq.1
\n" ); document.write( "\"p%2Bq=6+\".........eq.2
\n" ); document.write( "____________\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3q=-p%2B16\".......eq.1
\n" ); document.write( "\"q=-p%2B6+\".........eq.2
\n" ); document.write( "____________\r
\n" ); document.write( "\n" ); document.write( "\"q=-%281%2F3%29p%2B16%2F3\".......eq.1
\n" ); document.write( "\"q=-p%2B6+\".........eq.2
\n" ); document.write( "____________\r
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\n" ); document.write( "\n" ); document.write( "now find two points that lie on each line\r
\n" ); document.write( "\n" ); document.write( "\"q=-%281%2F3%29p%2B16%2F3\".......eq.1...set \"q=0\"\r
\n" ); document.write( "\n" ); document.write( "\"0=-%281%2F3%29p%2B16%2F3\"...solve for \"p\"\r
\n" ); document.write( "\n" ); document.write( "\"%281%2F3%29p=16%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"p%2F3=16%2F3\"...if denominator same, numerator must be same too\r
\n" ); document.write( "\n" ); document.write( "\"p=16\"\r
\n" ); document.write( "\n" ); document.write( "point is (\"16\",\"0\")=> x(or p)-intercept\r
\n" ); document.write( "\n" ); document.write( "\"q=-%281%2F3%29p%2B16%2F3\".......eq.1...set \"p=0\"\r
\n" ); document.write( "\n" ); document.write( "\"q=-%281%2F3%290%2B16%2F3\"...solve for \"p\"\r
\n" ); document.write( "\n" ); document.write( "\"q=16%2F3\"\r
\n" ); document.write( "\n" ); document.write( "point is (\"0\",\"16%2F3\")=> y(or q)-intercept\r
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\n" ); document.write( "\n" ); document.write( "\"q=-p%2B6+\".........eq.2\r
\n" ); document.write( "\n" ); document.write( "\"q=-p%2B6\".......eq.2...set \"q=0\"\r
\n" ); document.write( "\n" ); document.write( "\"0=-p%2B6\"...solve for \"p\"\r
\n" ); document.write( "\n" ); document.write( "\"p=6\"\r
\n" ); document.write( "\n" ); document.write( "point is (\"6\",\"0\")=> x(or p)-intercept\r
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\n" ); document.write( "\n" ); document.write( "\"q=-p%2B6\".......eq.2...set \"p=0\"\r
\n" ); document.write( "\n" ); document.write( "\"q=0%2B6\"...solve for \"p\"\r
\n" ); document.write( "\n" ); document.write( "\"q=6\"\r
\n" ); document.write( "\n" ); document.write( "point is (\"0\",\"6\")=> y(or q)-intercept\r
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\n" ); document.write( "\n" ); document.write( "plot points (\"16\",\"0\") and (\"0\",\"16%2F3\") and draw a line \"q=-%281%2F3%29p%2B16%2F3\"\r
\n" ); document.write( "\n" ); document.write( "plot points (\"6\",\"0\") and (\"0\",\"6\")and draw a line \"q=-p%2B6\"\r
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