document.write( "Question 922901: I require help with this question. -start- Ten liters of 40% acid solution is made by mixing a 20% and a 50% solution. How much of the 20% solution is required to get the specified concentration? -end- \n" ); document.write( "
Algebra.Com's Answer #559834 by ankor@dixie-net.com(22740)\"\" \"About 
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Ten liters of 40% acid solution is made by mixing a 20% and a 50% solution.
\n" ); document.write( "How much of the 20% solution is required to get the specified concentration?
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\n" ); document.write( "let x = amt of 20% solution required
\n" ); document.write( "the resulting amt is to be 10 lt, therefore
\n" ); document.write( "(10-x) = amt of 50% solution
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\n" ); document.write( "Write an amt of acid equation, using the decimal equiv of per cents
\n" ); document.write( ".2x + .5(10-x) = .4(10)
\n" ); document.write( ".2x + 5 - .5x = 4
\n" ); document.write( ".2x - .5x = 4 - 5
\n" ); document.write( "-.3x = -1
\n" ); document.write( "x = -1/-.3
\n" ); document.write( "x = +3\"1%2F3\" liters of the 20% solution
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