document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78082>Question 78082</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Martina leaves home at 9 a.m., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55981 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55981\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 24*x=48(x-2)<BR>\n" );
document.write( "24x=48x-96<BR>\n" );
document.write( "24x-48x=-96<BR>\n" );
document.write( "-24x=-96<BR>\n" );
document.write( "x=-96/-24<BR>\n" );
document.write( "x=4 hours after Martina leave John will catch her.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "24*4=48*2<BR>\n" );
document.write( "96=96 miles from the start is where they meet. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );