document.write( "Question 922832: the perimeter of a rectangle os 18ft, and the area of the rectangle is 20 sq ft. what is the width of the rectangle ?
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Algebra.Com's Answer #559803 by MathTherapy(10552) $\"\"$ $\"About$

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the perimeter of a rectangle os 18ft, and the area of the rectangle is 20 sq ft. what is the width of the rectangle ?
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document.write( "Let width and length, be W and L, respectively
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document.write( "Then: 2(W + L) = 18_____2(W + L) = 2(9)____W + L = 9_____L = 9 - W ----- eq (i)
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document.write( "Also, LW = 20 ------ eq (ii)
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document.write( "W(9 - W) = 20 ------- Substituting 9 - W for L in eq (ii)
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document.write( "(W - 5)(W - 4) = 0
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document.write( "W, or width =              OR             
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document.write( "Note that:
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document.write( "If width = 5, then length = 4
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document.write( "If width = 4, then length = 5 \n" );
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