document.write( "Question 922802: Assume that heights of men are normally distributed with a mean of 69.0 in. and a standard deviation of 2.8 in. The standard casket has an inside length of 78 in. A manufacturer of caskets wants to reduce production costs by making smaller caskets. What inside length would fit all men expect the tallest 1%? \n" ); document.write( "
Algebra.Com's Answer #559793 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! Population: mean of 69.0 in. and a standard deviation of 2.8 in \n" ); document.write( "z = invNorm(.99) = 2.326 \n" ); document.write( " \n" ); document.write( "2.326(2.8) + 69 = X = 75.5 \n" ); document.write( "What inside length would fit all men expect the tallest 1%: 75\" rounded \n" ); document.write( " |