document.write( "Question 922845: Hello, I'm not sure where this problem is supposed to go so I just put it here.\r
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document.write( "Use synthetic division to show that x=7 is a root of the equation x^3-9x^2-1x+105=0.
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document.write( "Then, use the result to factor the polynomial completely into the form (x+A)(x+B)(x+C).\r
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document.write( "thank you in advance! \n" );
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Algebra.Com's Answer #559759 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! The polynomial was made using binomial factors. When they were multiplied and the result simplified and put into general form, the result became \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, you want to test for different possible binomial factors to see which ones are pefect divisors of the polynomial, meaning the remainder is zero. You are guided with the instruction to first test the root x=7, which corresponds to the binomial factor of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "_______7_____|______1______-9______-1________105 \n" ); document.write( "_____________|_ \n" ); document.write( "_____________|_____________7_______-14_______-105 \n" ); document.write( "_____________|_______________________________________ \n" ); document.write( "____________________1_______-2_____-15________0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The remainder is 0; x=7 is a root of the given polynomial. \n" ); document.write( "The resulting quotient means that the quotient is really \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simple factoring trials should be enough \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The factorization for the given equation is |