document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78063>Question 78063</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In this question the paper gives you a description and you're to put it into a quadratic equation.\r<BR>\n" );
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document.write( "The sum of the square of a number and 4 times the number is 12. \r<BR>\n" );
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document.write( "The equation I got was x^2+4x=12 I'm not sure if it's right but that's what I got. When I went to solve it though I didn't get what my teacher told me I would get, I didn't get two numbers in the end because the square root of the number I got was a decimal and she said we would get whole numbers. Can anyone help? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55973 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55973\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> your equation is right...what was your method of solution?...factoring is probably the easiest\r<BR>\n" );
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document.write( "subtracting 12 from both sides gives x^2+4x-12=0...factoring gives (x-2)(x+6)=0...this means x=2 and x=-6\r<BR>\n" );
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document.write( "you mentioned taking the square root of a number...if you use the quadratic formula, the equation must equal zero before you start </SPAN>\n" );
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