document.write( "Question 922820: please help me i am stuck with this problem..............
\n" ); document.write( "IF x^2 =r^2+2rs+s^2,y^2=s^2,x>0,and y>0,then x/y=
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Algebra.Com's Answer #559726 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
First find:
\n" ); document.write( " $\"+x%5E2+%2F+y%5E2+=+%28+r%5E2+%2B+2r%2As+%2B+s%5E2+%29+%2F+s%5E2+\"$
\n" ); document.write( " $\"+x%5E2+%2F+y%5E2+=+%28+r+%2B+s+%29%5E2+%2F+s%5E2+\"$
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\n" ); document.write( "Take the square root of both sides. Since they say
\n" ); document.write( " $\"+x%3E0+\"$ and $\"+y%3E0+\"$ , they want positive square roots,
\n" ); document.write( "not negative roots
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\n" ); document.write( " $\"+x%2Fy+=+%28+r%2Bs+%29+%2F+s+\"$
\n" ); document.write( "or, what is the same:
\n" ); document.write( " $\"+x%2Fy+=+r%2Fs+%2B+1+\"$ \r
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