document.write( "Question 922700: aviva has a total of 56 coins, all which are either dimes or nickels . the total value of the coins is $5.05. find the number of each coin? \n" ); document.write( "

Algebra.Com's Answer #559691 by Edwin McCravy(20059) $\"\"$ $\"About$

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Aviva has a total of 56 coins, all which are either dimes or nickels. The total
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document.write( "Let the number of nickels be x\r\n" );
document.write( "Then the number of dimes, using \r\n" );
document.write( "ONE PART = TOTAL MINUS OTHER PART,\r\n" );
document.write( "is 56-x.  \r\n" );
document.write( "                      Value      Value\r\n" );
document.write( "Type       Number       of         of\r\n" );
document.write( " of          of        EACH       ALL\r\n" );
document.write( "coin        coins      coin      coins\r\n" );
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document.write( "NICKELS      x        $0.05    $0.05x \r\n" );
document.write( "DIMES      56-x       $0.10    $0.10(56-x)\r\n" );
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document.write( "TOTALS      56        -----    $5.05\r\n" );
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document.write( " The equation comes from the column on the right\r\n" );
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document.write( "0.05x + 0.10(56-x) = 5.05\r\n" );
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document.write( "Get rid of decimals by multiplying every term by 100\r\n" );
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document.write( "     5x + 10(56-x) = 505\r\n" );
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document.write( "    5x + 560 - 10x = 505\r\n" );
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document.write( "         -5x + 560 = 505\r\n" );
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document.write( "               -5x = -55\r\n" );
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document.write( "                 x = 11 = the number of nickels\r\n" );
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document.write( "The number of dimes is 56-x or 56-11 or 45 dimes.\r\n" );
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document.write( "Checking:  11 nickels is $0.55 and 45 dimes is $4.50\r\n" );
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document.write( "And indeed $0.55+4.50 = $5.05.\r\n" );
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document.write( "Edwin

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