document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78065>Question 78065</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.  Find the length of a shorter leg of a right triangle if the longer leg is 10 miles more than the shorter leg and the hypotemuse is 10 miles less than twice the shorter leg.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55969 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55969\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the length of a shorter leg of a right triangle if the longer leg is 10 miles more than the shorter leg and the hypotemuse is 10 miles less than twice the shorter leg.<BR>\n" );
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document.write( "Let the length of the shorter leg be \"x\" miles.<BR>\n" );
document.write( "Longer leg is \"x+10\".<BR>\n" );
document.write( "Hypotenuse is \"2x-10\".<BR>\n" );
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document.write( "EQUATION: Use Pythagoras to get:<BR>\n" );
document.write( "x^2 + (x+10)^2= (2x-10)^2<BR>\n" );
document.write( "x^2 + x^2+20x+100 = 4(x^2-10x+25)<BR>\n" );
document.write( "2x^2+20x+100 = 4x^2-40x+100<BR>\n" );
document.write( "2x^2-60x=0<BR>\n" );
document.write( "2x(x-30)=0<BR>\n" );
document.write( "x=30 (this is the length of the shorter leg)<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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