document.write( "Question 922706: Find the value of k so that 2k + 2, 5k - 11, and 7k - 13 will form an arithmetic progression. \n" ); document.write( "
Algebra.Com's Answer #559683 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Find the value of k so that 2k + 2, 5k - 11, and 7k - 13 will form an arithmetic progression.
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document.write( "In an arithmetic progression, the common difference, or d is obtained by SUBTRACTING the
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document.write( "1st term from the 2nd term, or by SUBTRACTING the 2nd term from the 3rd term. Thus, we get:
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document.write( "5k – 11 – (2k + 2) = 7k – 13 – (5k – 11)
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document.write( "5k – 11 – 2k – 2 = 7k – 13 – 5k + 11
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document.write( "3k – 13 = 2k – 2
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document.write( "3k – 2k = - 2 + 13 
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document.write( "\"highlight_green%28highlight_green%28k+=+11%29%29\" \n" );
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