document.write( "Question 78064: solve by factor completing the square
\n" ); document.write( "x^2 - 8x+10=0
\n" ); document.write( "x^2 - 8x= -10
\n" ); document.write( "(8/2)^2= 64/4= 16\r
\n" ); document.write( "\n" ); document.write( "x^2 - 8x + 16=-10 +16
\n" ); document.write( " what else to do after this step?
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Algebra.Com's Answer #55968 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2+-+8x+%2B+16=-10+%2B16\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+-+8x+%2B+16=6\" Combine like terms\r
\n" ); document.write( "\n" ); document.write( "\"%28x-4%29%5E2=6\" Since the left side is a perfect square it becomes \"%28x-4%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "If you want to solve for x then you simply take the square root of both sides\r
\n" ); document.write( "\n" ); document.write( "\"x-4=0%2B-sqrt%286%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=0%2B-sqrt%286%29%2B4\" Add 4 to both sides\r
\n" ); document.write( "\n" ); document.write( "So our answer is:\r
\n" ); document.write( "\n" ); document.write( "\"x=sqrt%286%29%2B4\" or \"x=-sqrt%286%29%2B4\"
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