document.write( "Question 922685: a boat travels 45 mi upstream (against the current) in 5h. The boat travels the same distance downstream in 3h. What is the rate of the current? \n" ); document.write( "
Algebra.Com's Answer #559676 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! a boat travels 45 mi upstream (against the current) in 5h. The boat travels the same distance downstream in 3h. What is the rate of the current? \n" ); document.write( "*** \n" ); document.write( "let x=rate of boat in still water \n" ); document.write( "let c=rate of current \n" ); document.write( "(x+c)=rate of boat downstream \n" ); document.write( "(x-c)=rate of boat upstream \n" ); document.write( "distance/rate=travel time \n" ); document.write( "45/(x-c)=5 \n" ); document.write( "45/(x+c)=3 \n" ); document.write( ".. \n" ); document.write( "5x-5c=45 \n" ); document.write( "3x+3c=45 \n" ); document.write( ".. \n" ); document.write( "15x-15c=135 (mult. eq by 3) \n" ); document.write( "15x+15c=225 (mult. eq by 5) \n" ); document.write( "subtract: \n" ); document.write( "-30c=-90 \n" ); document.write( "c=3 \n" ); document.write( "What is the rate of the current? 3 mph \n" ); document.write( " |