document.write( "Question 922685: a boat travels 45 mi upstream (against the current) in 5h. The boat travels the same distance downstream in 3h. What is the rate of the current? \n" ); document.write( "
Algebra.Com's Answer #559676 by lwsshak3(11628)\"\" \"About 
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a boat travels 45 mi upstream (against the current) in 5h. The boat travels the same distance downstream in 3h. What is the rate of the current?
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\n" ); document.write( "let x=rate of boat in still water
\n" ); document.write( "let c=rate of current
\n" ); document.write( "(x+c)=rate of boat downstream
\n" ); document.write( "(x-c)=rate of boat upstream
\n" ); document.write( "distance/rate=travel time
\n" ); document.write( "45/(x-c)=5
\n" ); document.write( "45/(x+c)=3
\n" ); document.write( "..
\n" ); document.write( "5x-5c=45
\n" ); document.write( "3x+3c=45
\n" ); document.write( "..
\n" ); document.write( "15x-15c=135 (mult. eq by 3)
\n" ); document.write( "15x+15c=225 (mult. eq by 5)
\n" ); document.write( "subtract:
\n" ); document.write( "-30c=-90
\n" ); document.write( "c=3
\n" ); document.write( "What is the rate of the current? 3 mph
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