document.write( "Question 922696: how many milliliters of pure water must be added to 60 milliliters of a 20 percent salt solution to make a 12percent salt solution?
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Algebra.Com's Answer #559674 by srinivas.g(540) $\"\"$ $\"About$

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INitially we have 60 millilitres of solution with 20 % salt
\n" ); document.write( " so quantity of salt in the solution = 20% of 60 milliliters
\n" ); document.write( " = $\"+%2820%2F100%29%2A60\"$
\n" ); document.write( " = $\"%2820%2F5%29%2A3\"$
\n" ); document.write( " = $\"4%2A3\"$
\n" ); document.write( " = $\"12+\"$ millilitres
\n" ); document.write( "let assume v milliliters of pure water is added to the salt solution
\n" ); document.write( " so total quantity of salt solution now becomes 60 +v millilitres
\n" ); document.write( " quantity of salt after adding water is 12 % of (60+v) millilitres
\n" ); document.write( "but quantity of salt in the solution is remains same even after adding water to the salt solution
\n" ); document.write( " so 12 = 12 % of (60+v)
\n" ); document.write( " $\"+12+=+%2812%2F100%29%2A%2860%2Bv%29+\"$
\n" ); document.write( " multiply with $\"%28100%2F12%29\"$ on both sides
\n" ); document.write( " $\"+12%2A%28100%2F12%29+=+%2812%2F100%29%2A%2860%2Bv%29%2A%28100%2F12%29\"$
\n" ); document.write( " $\"+100=60%2Bv\"$
\n" ); document.write( " subtract 60 on both sides
\n" ); document.write( " $\"100-60+=60%2Bv-60\"$
\n" ); document.write( " 40 =v
\n" ); document.write( " so v= 40 millilitres
\n" ); document.write( "result : quantity of water added = 40 millilitres
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