document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=922680>Question 922680</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 5 more than twice the width the perimeter is 130 inches what is the area </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #559663 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=559663\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L + 2W = 130<BR>\n" );
document.write( "L = 2W+5<BR>\n" );
document.write( "2(2W+5) + 2W = 130<BR>\n" );
document.write( "4W+10 + 2W = 130<BR>\n" );
document.write( "6W + 10 = 130<BR>\n" );
document.write( "6W = 120<BR>\n" );
document.write( "W = 20<BR>\n" );
document.write( "If the width is 20, then the length is twice that plus 5, or 45<BR>\n" );
document.write( "L = 45 and W = 20 <BR>\n" );
document.write( "area = L*W or 900 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );